1.6.3) College Committee Formation (p. 62)

(a) AB, AC, AD, AE, AF, BC, BD, BE, BF, CD, CE, CF, DE, DF, EF

(b) 15 pairs

(c) AB = 1 pair

P(2 women) = 1/15 = .067

(d) This is a rather small probability and does cast some doubt that the subcommittee selection was made completely at random since such an outcome would occur about 6.7% of the time by chance alone.

 

1.6.4) College Committee Formation (cont.) (p. 62)

(a) C(6,2) = 6(5)/2 = 15

(b) C(2,2)C(4,0)/C(6,2) = 1/15

(c) C(4,4)C(8,0)/C(12,4) = 1/495

(d) The probability of all four chosen subcommittee members being women is much smaller.